Lotus Elan

Ignition Timing

PostPost by: redskatejbf » Thu Mar 05, 2009 10:13 pm

Hi,
I have a 43D4-41471F distributor fitted to a Big Valve engine, Iam aware that a advance of 26 to 27 degrees at 2,500 to 3,000 is the standard setting but I do not understand how the distributor produces that amount of advance when the static advance is say 9 degrees (with L.R.P.) and that it is fitted with counter-weights marked 7 Deg. advance. Can someone explain to a numpty how it produces an advance of 26 / 27 degrees. I have not been able to check if it does produces these figures so it may not anyway. I do recall being told of a statement by a Greek philosopher that `He who knows not and knows that he knows not, is a child, teach him` . Please do.
Regards John.
The lines fall unto me in pleasant places, yea I have a goodly heritage.
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PostPost by: paddy » Thu Mar 05, 2009 10:20 pm

The numbers stamped on the distributor weights are the maximum dynamic advance in terms of degrees at the distributor, and the advance at the crank is double this.

So I think with 9 degrees static the maximum total advance you will achieve (at the crank) will be 9 + 2 x 7 = 23.

That's my understanding anyway.

Paddy
1963 Elan S1
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PostPost by: redskatejbf » Thu Mar 05, 2009 10:37 pm

Thanks Paddy, that makes sense. And Ive had second thoughts on the philospher he was Chinese, Iam `confused` I think. :oops:
John.
The lines fall unto me in pleasant places, yea I have a goodly heritage.
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