Lotus Elan and Lotus Elan Plus 2 Forums

Hi,
I have a 43D4-41471F distributor fitted to a Big Valve engine, Iam aware that a advance of 26 to 27 degrees at 2,500 to 3,000 is the standard setting but I do not understand how the distributor produces that amount of advance when the static advance is say 9 degrees (with L.R.P.) and that it is fitted with counter-weights marked 7 Deg. advance. Can someone explain to a numpty how it produces an advance of 26 / 27 degrees. I have not been able to check if it does produces these figures so it may not anyway. I do recall being told of a statement by a Greek philosopher that `He who knows not and knows that he knows not, is a child, teach him` . Please do.
Regards John.

The numbers stamped on the distributor weights are the maximum dynamic advance in terms of degrees at the distributor, and the advance at the crank is double this.

So I think with 9 degrees static the maximum total advance you will achieve (at the crank) will be 9 + 2 x 7 = 23.

That's my understanding anyway.

Paddy

Thanks Paddy, that makes sense. And Ive had second thoughts on the philospher he was Chinese, Iam `confused` I think.
John.